Conclusion 1. What metal ion would you predict to be contained in the sample of unknown? Why?
A: Sodium, Na. Because when we put the unknown substance in the flame it turned orange just like Sodium.
2. Based on your results and observations would this method be practical to determine metals in a mixture? If not, why not?
A: No because if two substances are mixed it may let off a different color.
3. Explain the reason Potassium was visible when using the cobalt glass.
A: Because Cobalt is a brittle, hard, transition metal with magnetic properties similar to those of iron, which allowed us to see Potassium.
4. Explain the effect of the nitrate ion in solution on the color emission.
5. Give at least two reasons why the flame test is sometimes invalid. A: When solutions of metals are heated they give off characteristic colors. Sometimes the colors may seem alike but be totally different. There may also be a temperature difference.
6. What other means of qualitative analysis are used to identify metals? A: Qualitative analysis is used to separate and detect cations and anions in a sample substance.
Further Investigation
1. Explain the difference between emission and absorption spectra. A: Emission Spectra produces thin gases in which the atoms do not experience many collisions because of the low-density. An absorption spectra occurs when light passes through a cold, dilute gas and atoms in the gas absorb at characteristic frequencies; since the re-emitted light is unlikely to be emitted in the same direction as the absorbed photon, this gives rise to dark lines in the spectrum.
2. Advertising lights are produced and sealed tubes of various noble gases, which emit colored light when excited. Using references, explain the techniques used in producing the lights.
3. Use reference sources and determine the flame color of five additional metal ions.
4. What is a spectral line?
5. Compare the 2 methods. Why is spectroscopy superior to flame test?
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